2) as t from jqdltb 显示为:83.12 select round(83.125，再然后/100 如下所示: select int((83.121+0.005)*100)/100 as t from jqdltb 显示为:83.12 select int((83.124+0.005)*100)/100 as t from jqdltb 显示为:83.12 select int((83.125+0.005)*100)/100 as t from jqdltb 显示为:83.13 select int((83.126+0.005)*100)/100 as t from jqdltb 显示为:83.13 select int((83.129+0.005)*100)/100 as t from jqdltb 显示为:83.13 ---the--end--- ---create date:2012-03-30---- ， Access数据库中Round用法 四舍五入的问题 select round(83.124，2) as t from jqdltb 显示为:83.13 问题来了，2) as t from jqdltb 显示为:83.12 select round(83.126，然后*100，就是四舍五入怎么变成五舍六入了呢？ 下面是用这个方法来调整达到四舍五入的方法: 使用int函数和加0.005，。